Question

A body is traveling down an inclined plane of angle of ${30}^{\circ }$ with an acceleration of $2m/s^2$, leaves it with speed of $20m/s$. If the inclined plane is located at a certain height above the ground, find its velocity when it travels in the horizontal direction after $1\text{second}$.

• A. $11\sqrt{3}m/s$
• B. $11\sqrt{2}m/s$
• C. $10\sqrt{3}m/s$
• D. $11m/s$

Answer 1

The correct option is A $11\sqrt{3}m/s$

From first equation of motion,
$v=u+at$
$v=20+2\times 1=22m/s$
Hence,
$v_x=22\cos {30}^{\circ }=11\sqrt{3}m/s$
Velocity is constant in horizontal direction.