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Standard XII

Physics

Projectile from a Height

A body is tra...

Question

A body is traveling down an inclined plane of angle of $30^{\circ}$ with an acceleration of $2 m / s^{2}$ , leaves it with speed of $20 m / s$ . If the inclined plane is located at a certain height above the ground, find its velocity when it travels in the horizontal direction after $1 second$ .

11 \sqrt{3} m / s

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11 \sqrt{2} m / s

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10 \sqrt{3} m / s

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11 m / s

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Solution

The correct option is A $11 \sqrt{3} m / s$
From first equation of motion,
$v = u + a t$
$v = 20 + 2 \times 1 = 22 m / s$
Hence,
$v_{x} = 22 cos 30^{\circ} = 11 \sqrt{3} m / s$
Velocity is constant in horizontal direction.

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A body is traveling down an inclined plane of angle of 30∘ with an acceleration of 2 m/s2, leaves it with speed of 20 m/s. If the inclined plane is located at a certain height above the ground, find its velocity when it travels in the horizontal direction after 1 second.

The correct option is A 11√3 m/sFrom first equation of motion, v=u+at v=20+2×1=22 m/s Hence, vx=22cos30∘=11√3 m/s Velocity is constant in horizontal direction.

A body is traveling down an inclined plane of angle of $30^{\circ}$ with an acceleration of $2 m / s^{2}$ , leaves it with speed of $20 m / s$ . If the inclined plane is located at a certain height above the ground, find its velocity when it travels in the horizontal direction after $1 second$ .

The correct option is A $11 \sqrt{3} m / s$
From first equation of motion,
$v = u + a t$
$v = 20 + 2 \times 1 = 22 m / s$
Hence,
$v_{x} = 22 cos 30^{\circ} = 11 \sqrt{3} m / s$
Velocity is constant in horizontal direction.