Question

A body moves along a circular path of radius $10m$ and the coefficient of friction is $0.5$. What should be its angular velocity in $rad/s$ if it is not to slip from the surface?

(Take $g=10m{s}^{-2}$)

• A. $0.4$
• B. $0.3$
• C. $0.5$
• D. $0.7$

Answer 1

Answer: (D)

$0.7$

Here,
Centripetal force = Frictional force
$\Rightarrow$ $mr{\omega }^2=\mu mg$
$\therefore {\omega }^2=\frac{\mu g}{r}$
$\therefore {\omega }^2=\frac{0.5\times 10}{10}=0.5$
$\therefore \omega =0.707rad/s$