A body of 2 kg falls from rest. What will be its kinetic energy during the fall at the end of 2 s ? (Assume g = 10 $m / s^{2}$ )

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Solution

Mass of the body m = 2 kg
Initial speed u = 0
t = 2 s
g = 10 m/s².
For a freely falling body the final velocity at the end of t s is given by
v = u + gt = 0 + 10 x 2 m/s
= 20 m/s
Kinetic energy at the end of 2 s = ½ mv²
= ½ x 2 kg x (20 m/s)²
= 400 J

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