MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relative Velocity in 2D

A body of 2...

Question

A body of $2 k g$ falls from rest. what will be its kinetic energy during the fall at the end $2 s$ ? $(A s s u m e$ $g = 10 m / s^{2})$

Open in App

Solution

Given,
mass of body $= 2 k g$
time taken $= 2 s$

we know
$v = g t$

$v = 10 \times 2$
$v = 20 m / s$

$K . E = \frac{1}{2} m v^{2}$
$= 1 / 2 \times 2 \times 20 \times 20 = 400 J$

So, kinetic energy of body $= 400 J$

Suggest Corrections

thumbs-up

5

Similar questions

Q. A body of mass 2 kg is thrown vertically upwards with an initial velocity of 20 m/s. What will be its potential energy at the end of 2 s? Assume

g = 10 m / s^{2}

Q. A body of mass

2 k g

is thrown upward with initial velocity

20 m / s

2 s

find its kinetic energy will be:

(g = 10 m / s^{2})

A body dropped from the top of a tower falls through 40m during the last 2s of its fall. The height of the tower is ( $g = 10 m / s^{2}$ )

Q. If a body of mass 20 gm falls from a height 200 m and its total potential energy is converted into kinetic energy, at the point of contact of the body with earth surface, then what is the decrease in potential energy of the body? (

g = 10 m / s^{2}

)

Q. Hailstone at

0^{o} C

falls from a height of

1 k m

on an insulating surface converting whole of its kinetic energy into heat. What part of it will melt: (

g = 10 m / s^{2}, L_{i c e} = 330 \times 10^{3} J {k g}^{- 1}

)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Motion in 2D

PHYSICS

Watch in App

explore_more_icon

Explore more

Relative Velocity in 2D

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon