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Question

# A body of constant mass m=1kg moves under variable force F as shown. If at t=0,S=0 and velocity of the body is √20m/s and the force is always along direction of velocity then choose the incorrect options

A
velocity of the particle will increase upto S=2m and then decrease.
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B
the final velocity at S=6m is 10m/s
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C
the final velocity at S=6mis45m/s
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D
the acceleration is constant up to S=2m and then it is negative
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Solution

## The correct option is B the final velocity at S=6m is 10m/sw=12(6+2)10=40Jw=Δk⇒40=12m[v2−20]⇒40=v2−202⇒80+20=v2⇒v=10m/sHence,option (B) is correct answer.

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