A body of mass $0.05 k g$ is falling with acceleration $9.4 m s^{- 2}$ . The force exerted by air opposite to motion is____________N ( $g = 9.8 m s^{- 2}$ )

0.02

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0.20

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0.030

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Zero

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Solution

The correct option is A $0.02$
Given mass of the body $m = 0.05 k g$ and acceleration $a = 9.4 m / s^{2}$
Now force exerted by the ball $F_{b} = 0.05 \times 9.4 = 0.47 N$
Also force exerted by the air due to acceleration due to gravity $F_{a i r} = 0.05 \times 9.8 = 0.49 N$
Thus net force acting on the body when falling $F_{n e t} = 0.49 - 0.47 = 0.02 N$

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