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Second Law of Motion

A body of mas...

Question

A body of mass $0.05 k g$ is observed to fall with an acceleration of $9.5 m s^{- 2}$ .The opposing force of an air on the body is $(g = 9.8 m s^{- 2})$

0.015 N

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0.15 N

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0.030 N

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zero

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Solution

The correct option is D $0.015 N$
From,Newton's laws of motion,
$m g - F_{a i r} = m a$
or $F_{a i r} = m (g - a)$
$= 0.05 (9.8 - 9.5)$
$0.015 N$

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