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Question

A body of mass 1kg is moving in a vertical circular path of radius 1m. The difference between the kinetic energies at its highest and lowest positions is :

A
45J
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B
20J
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C
10J
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D
30J
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Solution

The correct option is A 20J
Kinetic energy is the energy possessed by a body of mass m due to its velocity v.
KE=12mv2
At the highest point velocity, vA=rg
KE=12mv2A
At the lowest point velocity, vB=5rg
KE=12mv2B
Difference in KE=12m(v2Bv2A)=12m(5rgrg)
=2mrg=2×1×1×10=20J

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