You visited us 229 times! Enjoying our articles? Unlock Full Access!

Work Energy Theorem Application

A body of mas...

Question

A body of mass $1 k g$ is rotating in a vertical circle of radius $1 m$ . What will be the difference in its kinetic energy at the top and bottom of the circle?
Take $g = 10 m / s^{2}$

50 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $20 J$
According to work energy theorem, $Δ K . E . = W$ and here work is done by the gravitational force.
$\Rightarrow Δ K . E . = W = m g (2 r) = 1 \times 10 \times 2 (1) = 20 J$

Suggest Corrections

Similar questions

1 k g

1 m

1 k g

1 m

4 m / s

g = 10 m / s^{2}

m

r

1 kg

1 m

4 m/s

6 N

g = 10 {m/s}^{2}

Join BYJU'S Learning Program