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Work Energy Theorem Application

A body of mas...

Question

A body of mass $1 k g$ is rotating in a vertical circle of radius $1 m$ . What will be the difference in its kinetic energy at the top and bottom of the circle?
Take $g = 10 m / s^{2}$

50 J

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30 J

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20 J

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10 J

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Solution

The correct option is B $20 J$
According to work energy theorem, $Δ K . E . = W$ and here work is done by the gravitational force.
$\Rightarrow Δ K . E . = W = m g (2 r) = 1 \times 10 \times 2 (1) = 20 J$

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