A body of mass $1 k g$ is thrown upwards with a velocity $20 m / s$ . It momentarily comes to rest after attending a height of $18 m$ . How much energy is lot due to air friction (in J)

10

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20

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30

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40

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Solution

The correct option is A $20$
Initial energy $= 0.5 \times m \times v^{2} = 0.5 \times 1 \times 20^{2} = 200 J$
Fianl energy $= m g h = 1 \times 10 \times 18 = 180 J$
Loss in energy $= 200 - 180 = 20 J$

Hence correct answer is option $B$

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A body of mass 1kg is thrown upwards with a velocity 20m/s. It momentarily comes to rest after attending a height of 18m . How much energy is lot due to air friction (in J)

The correct option is A 20Initial energy =0.5×m×v2=0.5×1×202=200JFianl energy =mgh=1×10×18=180J Loss in energy =200−180=20J Hence correct answer is option B

A body of mass $1 k g$ is thrown upwards with a velocity $20 m / s$ . It momentarily comes to rest after attending a height of $18 m$ . How much energy is lot due to air friction (in J)

The correct option is A $20$
Initial energy $= 0.5 \times m \times v^{2} = 0.5 \times 1 \times 20^{2} = 200 J$
Fianl energy $= m g h = 1 \times 10 \times 18 = 180 J$
Loss in energy $= 200 - 180 = 20 J$

Hence correct answer is option $B$