A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is $g = 9.8 m / s e c^{2}$

- 490 Joules

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+ 490 Joules

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- 980 Joules

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+ 980 Joules

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Solution

The correct option is D
+ 980 Joules

As the body moves in the direction of force therefore work done by gravitational force will be positive.

$W = F s = m g h = 10 \times 9.8 \times 10 = 980 J$

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