A body of mass 10 kg is moving with a velocity of $5 m / s$ . What is the work to be done to bring the body to rest?

125 J

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225 J

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- 125 J

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- 225 J

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Solution

The correct option is C - 125 J
Mass of the object: 10 kg
Initial velocity $= 5 m s^{- 1}$
Final Velocity $= 0 m s^{- 1}$
Work Done = Change in kinetic energy
= Final kinetic energy - Initial kinetic energy
$= \frac{1}{2} m v^{2} - \frac{1}{2} m u^{2}$
$= \frac{1}{2} m (v^{2} - u^{2})$
$= \frac{1}{2} 10 (0^{2} - 5^{2})$
= - 125 J (nagative sign indicates work done is opposite to the direction of motion)

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A body of mass 10 kg is moving with a velocity of 5 m/s. What is the work to be done to bring the body to rest?

A body of mass 10 kg is moving with a velocity of $5 m / s$ . What is the work to be done to bring the body to rest?