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Standard XII

Physics

Equations of Motion

A body of mas...

Question

A body of mass $10 kg$ is moving with a constant velocity $10 m/s$ . When a constant force acts for $4 s$ on it, it moves with a velocity $2 m/s$ in the opposite direction. The magnitude of force acting on the body is

10 N

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30 N

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45 N

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50 N

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Solution

The correct option is B $30 N$
Here initial velocity $= u = 10 m/s$
Final velocity $= v = - 2 m/s$
( $∵$ opposite direction)
Change in velocity $(v - u) = - 2 - 10 = - 12 m/s$ ;
We know that, $a = \frac{v - u}{t}$
$\Rightarrow a = - \frac{12}{4} = - 3 {m/s}^{2}$
Force acting on body, $F = m a = 10 \times (- 3) = - 30 N$
Magnitude, $F = 30 N$

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A body of mass 10 kg is moving with a constant velocity 10 m/s. When a constant force acts for 4 s on it, it moves with a velocity 2 m/s in the opposite direction. The magnitude of force acting on the body is

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