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Question

A body of mass 10 kg is moving with a constant velocity 10 m/s. When a constant force acts for 4 s on it, it moves with a velocity 2 m/s in the opposite direction. The magnitude of force acting on the body is

A
10 N
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B
30 N
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C
45 N
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D
50 N
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Solution

The correct option is B 30 N
Here initial velocity =u=10 m/s
Final velocity =v=2 m/s
( opposite direction)
Change in velocity (vu)=210=12 m/s;
We know that, a=vut
a=124=3 m/s2
Force acting on body, F=ma=10×(3)=30 N
Magnitude, F=30 N

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