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Standard XII

Physics

Calorimetry

A body of mas...

Question

A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 sec is (J =4.2 joule/cal and g=9.8 $m / s^{2}$ )

9.33 cal

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10.21 cal

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12.67 cal

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13.34 cal

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Solution

The correct option is A
9.33 cal

$W o r k d o n e = F o r c e \times D i s p l a c e m e n t = μ m g \times (v \times t)$
$W = (0.2) \times 2 \times 9.8 \times 2 \times 5 j o u l e$
Heat generation Q= $\frac{W}{J} = \frac{0.2 \times 2 \times 9.8 \times 2 \times 5}{4.2} = 9.33 c a l$

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A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 sec is (J =4.2 joule/cal and g=9.8 m/s2)

The correct option is A 9.33 cal Workdone=Force×Displacement=μ mg×(v×t) W=(0.2)×2×9.8×2×5 joule Heat generation Q=WJ=0.2×2×9.8×2×54.2=9.33 cal

A body of mass 2 kg is being dragged with uniform velocity of 2 m/s on a rough horizontal plane. The coefficient of friction between the body and the surface is 0.20. The amount of heat generated in 5 sec is (J =4.2 joule/cal and g=9.8 $m / s^{2}$ )

The correct option is A
9.33 cal

$W o r k d o n e = F o r c e \times D i s p l a c e m e n t = μ m g \times (v \times t)$
$W = (0.2) \times 2 \times 9.8 \times 2 \times 5 j o u l e$
Heat generation Q= $\frac{W}{J} = \frac{0.2 \times 2 \times 9.8 \times 2 \times 5}{4.2} = 9.33 c a l$