A body of mass $2 k g$ is floating in the liquid of density $900 {k g m}^{- 3}$ . The weight of liquid displaced by it is

20 d y n e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N o n e o f t h e a b o v e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $20 N$
Solution
By the law of flotation,
weight of floating object = weight of
fluid displayed
weight of object = mg = $2 \times 10 = 20 N$
weight of liquid displayed = 20 N

Suggest Corrections

Similar questions

Write true or false for each statement:

(a) Equal volumes of the two different substances have equal masses.

(b) The density of a piece of brass will change by changing its size or shape.

(d) Relative density of water is 1.0.

(e) Relative density of a substance is expressed in g $c m^{-} 3$ .

(f) When a body is immersed in a liquid, the buoyant force experienced by the body is equal to the volume of the displaced by it.

(g) A body experiences the same buoyant force while floating in water or alcohol.

(h) A body experiences the same buoyant force when it floats or sinks in water.

(i) A body floats in a liquid when its weight becomes equal to the weight of the liquid displaced by its submerged part.

(j) A body while floating sinks in a liquid of low density than in high density.

Join BYJU'S Learning Program