A body of mass 2 kg is moving with a velocity 8 m/s on a smooth surface. If it is to be brought to rest in 4 seconds, then the force to be applied is

8 N

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4 N

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3 N

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1 N

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Solution

The correct option is B 4 N
Change in momentum $= m v$
$= 2 \times 8$
$= 16 K g m / s$
$t i m e = 4 s e c$
$F o r c e = \frac{16}{4} = 4 N$

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A body of mass 2 kg is moving with a velocity 8 m/s on a smooth surface. If it is to be brought to rest in 4 seconds, then the force to be applied is

The correct option is B 4 NChange in momentum=mv =2×8 =16Kgm/stime=4secForce=164=4N

The correct option is B 4 N
Change in momentum $= m v$
$= 2 \times 8$
$= 16 K g m / s$
$t i m e = 4 s e c$
$F o r c e = \frac{16}{4} = 4 N$