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Question

A body of mass 2 kg is thrown up vertically with K.E. of 490 joule. If the acceleration due to gravity is 9.8 m/s2, then the height at which the K.E. of the body becomes half its original value is given by


A

50 m

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B

12.5 m

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C

25 m

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D

10 m

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Solution

The correct option is B

12.5 m


Let h is that height at which the kinetic energy of the body becomes half its original value i.e. half of its kinetic energy will convert into potential energy

mgh=49022×9.8×h=4902h=12.5m.


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