Question

A body of mass 2 kg is thrown upward with an energy 490 J. The height at which its kinetic energy would become half of its initial kinetic energy will be $[g=9.8m/s^2]$

• A. 35 m
• B. 25 m
• C. 12.5 m
• D. 10 m

Answer 1

The correct option is C

12.5 m

If the kinetic energy would become half, then Potential energy = $\frac{1}{2}$ (Initial kinetic energy)

$\Rightarrow mgh=\frac{1}{2}\left[490\right]\Rightarrow 2\times 9.8\times h=\frac{1}{2}\left[490\right]\Rightarrow h=12.5m$