A body of mass 2 kg is thrown vertically upwards with an initial velocity of 20 m/s. What will be its potential energy at the end of 2 s? Assume g=10m/s2.
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Solution
From the second equation of motion, s=ut−12gt2 =20×2−12×10×4=40−20=20m So, potential energy at t = 2 s, P=mgh=2×10×20=400J