A body of mass $2$ kg makes an elastic collision with another body at rest and continues to move in the original direction with one fourth of its original speed. Find mass of the second body which collides with the first body.

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Solution

$m_{1} = 2 k g a n d V_{1} = (\frac{m_{1} - m_{2}}{m_{1} {+ m}_{2}}) u_{1} = \frac{u_{1}}{4}$
$m_{2} = 1.2 k g$

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A body of mass 2kg makes an elastic collision with another body at rest and continues to move in the original direction with one fourth of its original speed. Find mass of the second body which collides with the first body.

m1=2kgandV1=(m1−m2m1+m2)u1=u14m2=1.2kg

A body of mass $2$ kg makes an elastic collision with another body at rest and continues to move in the original direction with one fourth of its original speed. Find mass of the second body which collides with the first body.

$m_{1} = 2 k g a n d V_{1} = (\frac{m_{1} - m_{2}}{m_{1} {+ m}_{2}}) u_{1} = \frac{u_{1}}{4}$
$m_{2} = 1.2 k g$