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Standard XII

Physics

Limiting Friction

A body of mas...

Question

A body of mass 2 kg moves with a uniform velocity of $2 m s^{- 1}$ on a horizontal plane of coefficient of friction 0.2. If joules constant J is 4.2 J/cal and $g = 9.8 m s^{- 2}$ . Then the amount of heat generated in 5 seconds is

9.33 cal

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93.3 cal

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18.66 cal

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18.6 cal

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Solution

The correct option is A 9.33 cal
Work done by friction is the heat energy produced.
Therefore heat energy produced $= μ m g s .$
$s = v t = 2 \times 5 = 10 m$
Heat produced $= 0.2 \times 2 k g \times 9.8 m / s^{2} \times 10 m$

$= 39.2 J$

$= 39.2 / 4.2 c a l = 9.33 c a l$

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A body of mass 2 kg moves with a uniform velocity of 2 ms−1 on a horizontal plane of coefficient of friction 0.2. If joules constant J is 4.2 J/cal and g=9.8 ms−2. Then the amount of heat generated in 5 seconds is

The correct option is A 9.33 calWork done by friction is the heat energy produced.Therefore heat energy produced =μmgs.s=vt=2×5=10mHeat produced =0.2×2kg×9.8m/s2×10m =39.2J =39.2/4.2cal=9.33cal

A body of mass 2 kg moves with a uniform velocity of $2 m s^{- 1}$ on a horizontal plane of coefficient of friction 0.2. If joules constant J is 4.2 J/cal and $g = 9.8 m s^{- 2}$ . Then the amount of heat generated in 5 seconds is

The correct option is A 9.33 cal
Work done by friction is the heat energy produced.
Therefore heat energy produced $= μ m g s .$
$s = v t = 2 \times 5 = 10 m$
Heat produced $= 0.2 \times 2 k g \times 9.8 m / s^{2} \times 10 m$

$= 39.2 J$

$= 39.2 / 4.2 c a l = 9.33 c a l$