A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to rest after 2 sec. If one wants to keep this body moving on the same surface with a velocity of 4 m/sec, the force required is
4 N
u=4 m/s, v=0, t= 2sec
v=u+at ⇒ 0=4+2a ⇒a=−2m/s2
∴ Retarding force = ma =2 × 2= 4 N
This force opposes the motion. If the same amount of force is applied in forward direction, then the body will move with constant velocity.