A body of mass $2 k g$ moving on a horizontal surface with an initial velocity of $4 m / s$ comes to rest after $2 s$ . If one wants to keep this body moving on the same surface with a velocity of $4 m / s$ , the force required is:

8 N

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4 N

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0 N

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2 N

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Solution

The correct option is B $4 N$
$V_{1} = 4 m / s$
$V_{2} = 0$
Force acting on body $F = m a = 2 \times \frac{V_{2} - V_{1}}{t} = 2 \times \frac{0 - 4}{2} = - 4 N$
To move the body with constant velocity $4 N$ force needs to be applied.

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A body of mass 2kg moving on a horizontal surface with an initial velocity of 4m/s comes to rest after 2s. If one wants to keep this body moving on the same surface with a velocity of 4m/s, the force required is:

The correct option is B 4NV1=4m/sV2=0Force acting on body F=ma=2×V2−V1t=2×0−42=−4NTo move the body with constant velocity 4N force needs to be applied.

A body of mass $2 k g$ moving on a horizontal surface with an initial velocity of $4 m / s$ comes to rest after $2 s$ . If one wants to keep this body moving on the same surface with a velocity of $4 m / s$ , the force required is:

The correct option is B $4 N$
$V_{1} = 4 m / s$
$V_{2} = 0$
Force acting on body $F = m a = 2 \times \frac{V_{2} - V_{1}}{t} = 2 \times \frac{0 - 4}{2} = - 4 N$
To move the body with constant velocity $4 N$ force needs to be applied.