A body of mass 2 kg moving with a velocity 3 m/s collides with a body of mass 1 kg moving with a velocity of 4 m/s in opposite direction. If the collision is head on and completely inelastic, then
A
Both particles move together with velocity (23)m/s
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B
The momentum of system is 2kg m/s throughout
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C
The momentum of system is 10 kg m/s
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D
The loss of KE of system is (493)J
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Solution
The correct option is D The loss of KE of system is (493)J In completely inelastic collision, m1u1−m2u2=(m1+m2)V 2×3−1×4=(2+1)V;V=23m/s
Net momentum of system P=m1u1−m2u2 2×3−1×4=2 kg m/s
Loss in KE=12m1u21+12m2u22−12(m1+m2)V2 =12×2×(3)2+12×(1)×(4)2−12×(2+1)×(23)2 =9+8−23=17−23=493J