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Newton's Laws for System of Particles

A body of mas...

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A body of mass 2kg is placed on a smooth horizontal surface .Two forces F1= 20N & F2=10√3N are acting on the body in direction making angle of 30 & 60 to the surface .The reaction of the surface on the body will be a)20N b)25N c)5N d)zero

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Q. A body of mass 2 kg is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5. If the horizontal force applied on the body is 2.5 N, the frictional force acting on the body will be ( g = 10

m s^{2}

)

10 N

acting on a body at an angle of

60^{0}

with the horizontal direction displaces the body through a distance of

2 m

along the surface of a floor. Calculate the work done. Now let the force or pull acting on the body makes an angle of

30^{0}

with the horizontal. What is the value of the force to displace the body through

2 m

along the surface of the floor?

5 k g - w t

is acting on a body of mass

5 k g

kept on a smooth horizontal surface at rest. If it acts for

10

seconds at an angle of

60^{\circ}

with the horizontal, find the distance travelled by the body. (Take

g = 10 m / s^{2})

Q. A body of mass

2

k g

is placed on a horizontal surface having coefficient of kinetic friction

0.4

and coefficient of static friction

0.5

. If a horizontal force of

2.5

N

is applied on the body then the frictional force acting on the body will be (

g = 10 m s^{- 2}

)

5 kg - wt

is acting on a body of mass

5 kg

kept on a smooth horizontal surface at rest. If it acts for

10

seconds at an angle of

60^{\circ}

with the horizontal, find the distance travelled by it along the surface (Take

g = 10 {m/s}^{2}

)

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