A body of mass $4 k g$ is moving with momentum of $8 k g m s^{- 1}$ . A force of $0.2 N$ acts on it in the direction of motion of the body for $10 s$ . The increase in kinetic energy is:

10 J

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8.5 J

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4.5 J

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4 J

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Solution

The correct option is B $4.5 J$
$M o m e n t u m = m a s s \times v e l o c i t y$
$p = m u = u = \frac{p}{m} = \frac{8 k g m s^{- 1}}{4 k g} = 2 m s^{- 1}$
$A c c e l e r a t i o n = \frac{F o r c e}{M a s s} \Rightarrow a = \frac{0.2 N}{4 k g} = 0.05 m s^{- 2}$
Distance travelled by the body in $10 s$ is
$d = u t + \frac{1}{2} a t^{2}$
$= (2 m s^{- 1}) (10 s) + \frac{1}{2} \times (0.050 m s^{- 2}) (10 s)^{2}$
$= 20 m + 2.5 m = 22.5 m$
Work done, $W = F d = (0.2 N) (22.5 m) = 4.5 J$
According to work-energy theorem
Increasing in kinetic energy $= W o r k d o n e = 4.5 J$ .

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A body of mass 4 kg is moving with momentum of 8 kg ms−1. A force of 0.2 N acts on it in the direction of motion of the body for 10 s. The increase in kinetic energy is:

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