A body of mass $5$ kg is acted upon by a variable force. The force varies with the distance covered by the body. What is the speed of the body when the body has covered $25$ m? Assume that the body starts from rest.

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Solution

$M = 5 k g$
Work done $= F . d$
Work done=change in K.E
$F * (25) = \frac{1}{2} m v^{2} - 0$
$\frac{10 * 25 * 2}{5} = v^{2}$
$v = 10 m / s$

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A body of mass 5kg is acted upon by a variable force. The force varies with the distance covered by the body. What is the speed of the body when the body has covered 25m? Assume that the body starts from rest.

M=5kgWork done=F.dWork done=change in K.EF∗(25)=12mv2−010∗25∗25=v2v=10m/s

A body of mass $5$ kg is acted upon by a variable force. The force varies with the distance covered by the body. What is the speed of the body when the body has covered $25$ m? Assume that the body starts from rest.

$M = 5 k g$
Work done $= F . d$
Work done=change in K.E
$F * (25) = \frac{1}{2} m v^{2} - 0$
$\frac{10 * 25 * 2}{5} = v^{2}$
$v = 10 m / s$