A body of mass 5 kg is suspended by the strings making angles 60- and 30- with the horizontal -a T1 - 25 Nb T2-25 Nc T1 - 25-3 Nd T2 - 25-3 NChoose the correct option- g-10 ms-2

From horizontal equilibrium, T_22 = T_1√(3)2 T_2 = √(3)T_1 From vertical equilibrium, T_2 √(3)2 + T_12 = 50 ⇒ T_1=25 N, T_2=25√(3) N ...

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Standard XIII

Physics

Applying NLM along 3 Axis

A body of mas...

Question

A body of mass 5 kg is suspended by the strings making angles 60º and 30º with the horizontal -
a) $T_{1} = 25 N$
b) $T_{2} = 25 N$
c) $T_{1} = 25 \sqrt{3} N$
d) $T_{2} = 25 \sqrt{3} N$
Choose the correct option. ( $g = 10 m s^{- 2}$ )

a, b

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a, d

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c, d

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b, c

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Solution

The correct option is B a, d
From horizontal equilibrium,
$\frac{T_{2}}{2} = \frac{T_{1} \sqrt{3}}{2}$
$T_{2} = \sqrt{3} T_{1}$
From vertical equilibrium,
$\frac{T_{2} \sqrt{3}}{2} + \frac{T_{1}}{2} = 50$
$\Rightarrow T_{1} = 25 N$ , $T_{2} = 25 \sqrt{3} N$

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A body of mass 5 kg is suspended by the strings making angles 60º and 30º with the horizontal - a) T1=25 N b) T2=25 N c) T1=25√3 N d) T2=25√3 N Choose the correct option. (g=10 ms−2)

The correct option is B a, dFrom horizontal equilibrium, T22=T1√32 T2=√3T1 From vertical equilibrium, T2√32+T12=50 ⇒T1=25 N, T2=25√3 N

A body of mass 5 kg is suspended by the strings making angles 60º and 30º with the horizontal -
a) $T_{1} = 25 N$
b) $T_{2} = 25 N$
c) $T_{1} = 25 \sqrt{3} N$
d) $T_{2} = 25 \sqrt{3} N$
Choose the correct option. ( $g = 10 m s^{- 2}$ )

The correct option is B a, d
From horizontal equilibrium,
$\frac{T_{2}}{2} = \frac{T_{1} \sqrt{3}}{2}$
$T_{2} = \sqrt{3} T_{1}$
From vertical equilibrium,
$\frac{T_{2} \sqrt{3}}{2} + \frac{T_{1}}{2} = 50$
$\Rightarrow T_{1} = 25 N$ , $T_{2} = 25 \sqrt{3} N$