A body of mass 5 kg is taken from a height 5 m to 15 m. Find the increase in its potential energy. Take $g = 10 m s^{- 2}$

500 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

150 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

250 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
500 J

Given, the mass of body $m = 5 k g,$ height $h_{1} = 5 m$ , height $h_{2} = 15 m$ and $g = 10 m s^{- 2}$ .

Increase in potential energy $= m g (h_{2} - h_{1}) = 5 \times 10 (15 - 5) = 500 J$

Suggest Corrections

Similar questions

5 k g

10 m

4 m

g = 10 m s^{- 2}

(g = 10 m / s^{2})

A body of mass 2 kg is dropped from a building of height 5m. The maximum kinetic energy body can attain is

A body of mass 5 kg falls from a height of 10 m to 4m. Calculate:

(i) the loss in potential energy of the body, and (ii) the total energy possessed by the body at any instant? (Take g=10 m $s^{- 2}$ ).

5 k g

10 m

4 m

g = 10 m s^{- 2}

Join BYJU'S Learning Program