A body of mass $50 k g$ has momentum of $3000 k g m s^{- 1}$ . Calculate:
The velocity of the body.
The kinetic energy of the body.

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Solution

Step 1: Given data
Mass of the body $(m)$ = $50 k g$
Momentum $(P) = 3000 k g m s^{- 1}$
Velocity $(v) = ?$
Step 2:
Par (1): Calculation
$M o m e n t u m = m a s s \times v e l o c i t y P = m v v = \frac{P}{m} . . . . . . . . . (a)$
$v = \frac{3000 k g m s^{- 1}}{50 k g} v = 60 m s^{- 1}$
Hence, velocity is $60 m s^{- 1} .$
Par (1): Calculation
According to the formula of kinetic energy,
$K i n e t i c e n e r g y = \frac{1}{2} \times m a s s \times {(v e l o c i t y)}^{2} K = \frac{1}{2} m v^{2} . . . . . . . (b)$
On, putting all the values in equation (b), we get
$K = \frac{1}{2} \times 50 k g \times {(60 m s^{- 1})}^{2} K = \frac{1}{2} \times 50 \times 60 \times 60 = 90, 000 J$
Hence, the kinetic energy of the body is $90, 000 J .$

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