A body of mass $50 g$ is moving with a velocity of $10 m s^{- 1}$ . It is brought to rest by a resistive force of $10 N$ . Find the retardation

2 m s^{- 2}

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0.2 m s^{- 2}

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200 c m s^{- 2}

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200 m s^{- 2}

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Solution

The correct option is C $200 m s^{- 2}$
Given that force is 10 N and mass as 50g which is also equal to $50 / 1000 = 1 / 20$ . We know that force is equal to $F = m \times a$
$10 = a \times 1 / 20$
$a = 20 \times 10 = 200 m / s^{2}$ .
Hence retardation is $200 m / s^{2}$ .

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