A bullet with velocity of 10 ms^-2 is brought to rest after penitrating a wooden plank of 4cm thickness. Calculate the retardation of the bullet.

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Solution

Stopping distance S=4cm =0. 04m

initial velocity =10 m/s
final velocity =0 (since object stops)

we know
v^2-u^2=2aS

so a= u^2/2s
= 1010/2.04
=100/0.08
=1250 m/s^2 is the amont of retardation

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A bullet with velocity of 10 ms​​​​​-2 is brought to rest after penitrating a wooden plank of 4cm thickness. Calculate the retardation of the bullet.

Stopping distance S=4cm =0. 04m ​​​​​​initial velocity =10 m/s final velocity =0 (since object stops) we know v^2-u^2=2aS so a= u^2/2s = 10*10/2*.04 =100/0.08 =1250 m/s^2 is the amont of retardation

A bullet with velocity of 10 ms^-2 is brought to rest after penitrating a wooden plank of 4cm thickness. Calculate the retardation of the bullet.

Stopping distance S=4cm =0. 04m

initial velocity =10 m/s
final velocity =0 (since object stops)

we know
v^2-u^2=2aS

so a= u^2/2s
= 1010/2.04
=100/0.08
=1250 m/s^2 is the amont of retardation