A bullet of mass 50g moving with an initial velocity 100m/s strikes a wooden block and comes to rest after penetrating a distance of 2 cm. Calculate the retardation caused by the wooden block

Open in App

Solution

Mass, m = 0.05 kg

Initial velocity, u = 100 m/s

Distance covered, S = 2 cm = 0.02 m

Let ‘a’ be the acceleration.

Using,

v^2 = u^2 + 2aS

=> 0 = 100^2 + 2a × 0.02

=> a = - 2.5 × 10^5 m/s2

So, retardation is 2.5 × 10^5 m/s2

Suggest Corrections

Similar questions

Q. A bullet of mass 50 g moving with an initial velocity of

100 m s^{1}

strikes a wooden block and comes to rest after penetrating a distance of 2cm in it calculate
(i) initial momentum of a bullet
(ii) final momentum of the bullet
(iii) retardation caused by the wooden block and
(iv) resistive force exerted by the wooden block

A bullet of mass 50 g moving with an initial velocity of 100 m $s^{- 1}$ strikes a wooden block and comes to rest after penetrating a distance 2 cm in it. Calculate
(i) initial momentum of the bullet,
(ii) final momentum of the bullet,
(iii) retardation caused by the wooden block, and
(iv) resistive force exerted by the wooden block

Q. A bullet of mass

50 g

moving with an initial velocity

100 m s^{- 1}

, strikes a wooden block and comes to rest after penetrating a distance 2 cm in it. Calculate :

A bullet moving with a velocity of 100m/s strikes a wooden block and comes to rest after penetrating a distance of 2cm .calulate retadatation caused by wooden block.

Q. a bullet of masd 50g moving with an intial velocity 100m/s,strikes awooden block and comes to rest after penetrating a distance 2cm in it .calculate: 1)initial momentum of the bullet 2) final momentum of rhe bullet , 3)retardation caused by the wooden block ,and 4) resistive force exerted by the wooden block

Join BYJU'S Learning Program

A bullet of mass 50g moving with an initial velocity 100m/s strikes a wooden block and comes to rest after penetrating a distance of 2 cm. Calculate the retardation caused by the wooden block

Mass, m = 0.05 kg Initial velocity, u = 100 m/s Distance covered, S = 2 cm = 0.02 m Let ‘a’ be the acceleration. Using, v^2 = u^2 + 2aS => 0 = 100^2 + 2a × 0.02 => a = - 2.5 × 10^5 m/s2 So, retardation is 2.5 × 10^5 m/s2

Mass, m = 0.05 kg

Initial velocity, u = 100 m/s

Distance covered, S = 2 cm = 0.02 m

Let ‘a’ be the acceleration.

Using,

v^2 = u^2 + 2aS

=> 0 = 100^2 + 2a × 0.02

=> a = - 2.5 × 10^5 m/s2

So, retardation is 2.5 × 10^5 m/s2