A bullet moving with a velocity of 100m/s strikes a wooden block and comes to rest after penetrating a distance of 2cm .calulate retadatation caused by wooden block.

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Solution

Mass, m = 0.05 kg

Initial velocity, u = 100 m/s

Distance covered, S = 2 cm = 0.02 m

(i) Initial momentum = mu = 0.05 × 100 = 5 Ns

(ii) Final momentum = mv = 0

(iii) Let ‘a’ be the acceleration.

Using,

v2 = u2 + 2aS

=> 0 = 1002 + 2a × 0.02

=> a = - 2.5 × 105 m/s2

So, retardation is 2.5 × 105 m/s2

(iv) F = ma = (0.05) × (- 2.5 × 105m/s2) = -12500 N

So, the Resistive force by the wooden block = 12500 N

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