A body of mass 'M' collides against a wall with a velocity v and retraces its path with the same speed. the change in momentum is ............. (take initial direction of velocity as positive)

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2Mv

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-2 Mv

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2Mv
Taking +x direction to be positive , and assuming ball was travelling in +x direction initially.
$P_{i} = M v$
After collision ball will move in -x direction
$P_{f} = - M v$
Change in momentum:
$Δ P = P_{i} - P_{f}$
$Δ P = M v + M v = 2 M v$

Suggest Corrections

Similar questions

A body of mass 'M' collides against a wall with a velocity v and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)

Q. A body of mass M collides against a well with a velocity

ν

and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive )

Q. A body of mass 'M' collides against a wall with a velocity 'v' and retraces its path with the same velocity, the change in momentum is

Q. A body of mass

M

collides against a wall with velocity

V

and rebounds with the same speed. Its magnitude of change in momentum is:

Q. If a body of mass M collides against a wall with velocity V and rebounds with the same speed, then its change of momentum will be

Join BYJU'S Learning Program

A body of mass 'M' collides against a wall with a velocity v and retraces its path with the same speed. the change in momentum is ............. (take initial direction of velocity as positive)

The correct option is C 2MvTaking +x direction to be positive , and assuming ball was travelling in +x direction initially.Pi=MvAfter collision ball will move in -x directionPf=−MvChange in momentum:ΔP=Pi−PfΔP=Mv+Mv=2Mv

The correct option is C 2Mv
Taking +x direction to be positive , and assuming ball was travelling in +x direction initially.
$P_{i} = M v$
After collision ball will move in -x direction
$P_{f} = - M v$
Change in momentum:
$Δ P = P_{i} - P_{f}$
$Δ P = M v + M v = 2 M v$