A body of mass M collides against a well with a velocity $ν$ and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive )

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 M ν

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M ν

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2 M ν

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2 M ν$
initial momentum=mu
final momentum=-mu(- sign indicates change in direction)
net change= initial momentum - final momentum
$= m u - (- m u)$
$= 2 m u$
Option $B$ is correct answer.

Suggest Corrections

Similar questions

Q. A body of mass 'M' collides against a wall with a velocity v and retraces its path with the same speed. the change in momentum is ............. (take initial direction of velocity as positive)

A body of mass 'M' collides against a wall with a velocity v and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)

Q. A body of mass 'M' collides against a wall with a velocity 'v' and retraces its path with the same velocity, the change in momentum is

Q. A body of mass

M

collides against a wall with velocity

V

and rebounds with the same speed. Its magnitude of change in momentum is:

Q. If a body of mass M collides against a wall with velocity V and rebounds with the same speed, then its change of momentum will be

Join BYJU'S Learning Program

A body of mass M collides against a well with a velocity ν and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive )

The correct option is B 2Mνinitial momentum=mufinal momentum=-mu(- sign indicates change in direction)net change= initial momentum - final momentum=mu−(−mu)=2muOption B is correct answer.

A body of mass M collides against a well with a velocity $ν$ and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive )

The correct option is B $2 M ν$
initial momentum=mu
final momentum=-mu(- sign indicates change in direction)
net change= initial momentum - final momentum
$= m u - (- m u)$
$= 2 m u$
Option $B$ is correct answer.