A body of mass M collides with a wall with velocity V and rebounds with the same speed. Its change in momentum is equal to :

Zero

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2MV

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3MV

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Solution

The correct option is C 2MV
$Δ P = P_{1} - P_{2}$ $[$ change in momentum $]$
$= M V - (- M V) = - 2 M V$
negative sign denotes direction.
Hence option C is correct.

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A body of mass M collides with a wall with velocity V and rebounds with the same speed. Its change in momentum is equal to :

The correct option is C 2MVΔP=P1−P2 [ change in momentum]=MV−(−MV)=−2MVnegative sign denotes direction.Hence option C is correct.

The correct option is C 2MV
$Δ P = P_{1} - P_{2}$ $[$ change in momentum $]$
$= M V - (- M V) = - 2 M V$
negative sign denotes direction.
Hence option C is correct.