CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass m is projected with a velocity u making an angle θ with horizontal. Its horizontal range is R. The body splits into two equal parts at the highest point and one of the particle comes to rest. Then, the horizontal distance travelled by the other particle from the point of projection is

A
3R2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
R2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3R2
At highest point horizontal velocity of particle before splitting =ucosθ
using linear momentum conservation

mucosθ=m2v+m2(0)

v=2ucosθ
Since the horizontal component =2 times the initial velocity so range will also become twice since time depends only on vertical component of velocity

distance travelled =R2+R=3R2

54806_4379_ans.png

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed and Velocity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon