1
Question
A body is projected from the ground for horizontal range 100 m. At the highest point of its path it breaks apart into two identical part P and Q. If P comes to rest, than the horizontal distance of the landing point of part Q, from the point of projection is:
A body is projected from the ground for horizontal range 100 m. At the highest point of its path it breaks apart into two identical part P and Q. If P comes to rest, than the horizontal distance of the landing point of part Q, from the point of projection is:
Open in App
Solution
The correct option is C 150 m
As there is no external force acting on the system If the body wouldn't break into 2 pieces it would land at a distance of 100 mThen its center of mass would be at 100 mEven if the body breaks the center of mass of the system should remain at 100 mAs one of the pieces falls down vertically it reaches 50 m2m(100)=m(50)+mxx=150m
As there is no external force acting on the system
If the body wouldn't break into 2 pieces it would land at a distance of 100 m
Then its center of mass would be at 100 m
Even if the body breaks the center of mass of the system should remain at 100 m
As one of the pieces falls down vertically it reaches 50 m
2m(100)=m(50)+mx
x=150m
Suggest Corrections
1
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
