Question

A projectile of mass $2\text{m}$ explodes at the highest point of its path. It breaks into two equal parts. One part retraces its path. Find the distance of the second part from the point of projection when it finally lands on the ground. Given that range of the projectile would be $200\text{m}$ if no explosion had taken place.

• A. $100\text{m}$
• B. $400\text{m}$
• C. $200\text{m}$
• D. $150\text{m}$

Answer 1

The correct option is B $400\text{m}$

As there is no horizontal force acting, so the path of $COM$ will not change.

Let the second mass fall at a distance $x$ from the final position of COM.

Given: range of projectile (if no explosion had take place), $R=200\text{m}.$
Take the coordinate of $COM$ at the point of landing = $(0,0)$


$\therefore m(-R)+m\left(x\right)=0$
or $x=R=200\text{m}$

So, distance of second mass from the point of projection is $R+x=400\text{m}$