A body of mass $m$ is thrown at an angle $θ$ to the horizontal with the initial velocity $v_{0}$ . Assuming the air drag to be negligible, find the momentum increment $Δ p$ that the body acquires over the first $t$ seconds of motion.

Δ p = m g t

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Δ p = 2 m g t

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Δ p = 3 m g t

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Δ p = 4 m g t

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Solution

The correct option is C $Δ p = m g t$
Change in momentum will be equal to the impulse being imparted on it .
$△ p = F \times t$
$△ p = m \times g \times t$

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A body of mass m is thrown at an angle θ to the horizontal with the initial velocity v0. Assuming the air drag to be negligible, find the momentum increment Δp that the body acquires over the first t seconds of motion.

The correct option is C Δp=mgtChange in momentum will be equal to the impulse being imparted on it .△p=F×t△p=m×g×t

A body of mass $m$ is thrown at an angle $θ$ to the horizontal with the initial velocity $v_{0}$ . Assuming the air drag to be negligible, find the momentum increment $Δ p$ that the body acquires over the first $t$ seconds of motion.

The correct option is C $Δ p = m g t$
Change in momentum will be equal to the impulse being imparted on it .
$△ p = F \times t$
$△ p = m \times g \times t$