1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A body of mess 10 kg lies on a rough horizontal surface an acceleration of 5 m sâˆ’2 and when the horizontal force is doubled, it gets an acceleration of 18 m sâˆ’2. Then the coefficient of friction between the body and the horizontal surface is: (assume g = 10 m sâˆ’2)

A
0.2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
0.8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.4
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
0.6
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B 0.8Given : m=10 kg g=10m/s2 Let the horizontal force acting on the body be F.Acceleration of the body a=5m/s2∴ F−f=maOr F−f=(10)(5)=50 N ....(1)Now the horizontal force gets doubled i.e. F′=2FNew acceleration a′=18m/s2∴ F′−f=ma′Or 2F−f=(10)(18)=180 N ....(2)Subtracting (1) from (2) we get F=180−50=130 NPutting this in (1), 130−f=50We get f=80 NThus coefficient of friction μ=fmg∴ μ=8010×10=0.8

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Acceleration
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program