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Question

# A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of 5m/s2. And when the horizontal force is doubled, it gets an acceleration of 18m/s2. The coefficient of friction between the body and the horizontal surface is (Take g=10m/s2)

A
0.2
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B
0.4
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C
0.6
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D
0.8
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Solution

## The correct option is B 0.8Let the coefficient of friction be μ.Normal Force, N=mgTherefore frictional force f=μmgWhen force is F:Acceleration a=F−fm ⇒5m=F−fWhen force is 2F:Acceleration a=2F−fm ⇒18m=2F−fComparing both equations and eliminating F:10m=2F−2f18m=2F−f⇒8m=f=μmg⇒8=μg⇒μ=8/10=0.8

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