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Question

A block of weight 100N is pushed by a force F on a horizontal rough plane moves with an acceleration 1 m/s2, when force is doubled its acceleration becomes 10m/s2. The coefficient of friction is____(g=10ms2)

A
0.2
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B
0.4
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C
0.8
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D
0.5
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Solution

The correct option is C 0.8

Given that,

Weight, W=100N

Acceleration, a=1m/s2

Acceleration when force is double, a=10m/s2


Now, Let the External Force be F and friction force be f.

Then,

Ffs=ma

FμN=ma

Fμ100=10×1

Fμ100=10....(I)


We know, When Force is doubled,

Then,

2Ffs=ma

2FμN=ma

2Fμ100=10×10

2Fμ100=100....(II)


Now, from equation (I) and (II)

F=90N

Now, put the value of F in equation (I)

90μ100=10

μ100=1090

μ=80100

μ=0.8

Hence, the coefficient of restitution is 0.8


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