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Question

# A block of weight 100N is pushed by a force F on a horizontal rough plane moves with an acceleration 1 m/s2, when force is doubled its acceleration becomes 10m/s2. The coefficient of friction is____(g=10msâˆ’2)

A
0.2
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B
0.4
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C
0.8
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D
0.5
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Solution

## The correct option is C 0.8Given that, Weight, W=100N Acceleration, a=1m/s2 Acceleration when force is double, a=10m/s2 Now, Let the External Force be F and friction force be f. Then, F−fs=ma F−μN=ma F−μ100=10×1 F−μ100=10....(I) We know, When Force is doubled, Then,2F−fs=ma 2F−μN=ma 2F−μ100=10×10 2F−μ100=100....(II) Now, from equation (I) and (II) F=90N Now, put the value of F in equation (I) 90−μ100=10 −μ100=10−90 μ=80100 μ=0.8 Hence, the coefficient of restitution is 0.8

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