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Problem Solving

A block of we...

Question

A block of weight $100$ N is pushed by a force $F$ on a horizontal rough plane moves with an acceleration $1$ $m / s^{2}$ , when force is doubled it's acceleration becomes $10$ $m s^{- 2}$ . The coefficient of friction is:
( $g = 10$ $m s^{- 2}$ )

0.4

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0.6

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0.5

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0.8

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Solution

The correct option is D $0.8$
It is given :
$m g = 100 N$
$m = 10 k g$ ;
$a_{1} = 1 m / s^{2}, a_{2} = 10 m / s^{2}$
$F - f = m a_{1}, 2 F - f = m a_{2}$ ; where $f$ is force of friction,
Solving simultaneously we get,
$f = 80 = μ m g \Rightarrow μ = 0.8$

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