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Question

A body of mass 2 Kg is moving on a rough horizontal surface with an acceleration of 5ms2 and when the horizontal force is doubled,it gets an an acceleration of 18ms2. Then the coefficient of friction between the body and horizontal surface is: (assumeg=10ms2)

A
0.2
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B
0.8
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C
0.4
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D
1
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Solution

The correct option is B 0.8

Initially, when the body of mass 2 Kg is moving on a rough surface with an acceleration of 5 ms-2. Then,

ma1=Ff

10=Ff.............(1)

When the horizontal force is doubled, it gets an acceleration of 18 ms-2. Then,

ma2=2Ff

36=2Ff........(2)

Solving equation (1) and (2)

36=2Ff

10=Ff

f=16N

f=μR

μ=fR

μ=fmg

μ=1620

μ=0.8


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