1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A body of mass 2 Kg is moving on a rough horizontal surface with an acceleration of 5msâˆ’2 and when the horizontal force is doubled,it gets an an acceleration of 18msâˆ’2. Then the coefficient of friction between the body and horizontal surface is: (assumeg=10msâˆ’2)

A
0.2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
0.8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.4
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
1
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B 0.8Initially, when the body of mass 2 Kg is moving on a rough surface with an acceleration of 5 ms-2. Then, ma1=F−f 10=F−f.............(1) When the horizontal force is doubled, it gets an acceleration of 18 ms-2. Then, ma2=2F−f 36=2F−f........(2) Solving equation (1) and (2) 36=2F−f 10=F−f f=16N ∵f=μR μ=fR μ=fmg μ=1620 μ=0.8

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Equations of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program