The velocity is given as,
12Iω2=12mv2
12×3(2)2=12×12×v2
v=1m/s
Thus, the speed of the body is 1m/s.
A diver having a moment of inertia of 6.0 kg-m2 about an axis through its centre of mass rotates at an angular speed of 2 rad/s about this axis. If he folds his hands and feet to decrease the moment of inertia to 5.0 kg-m2, what will be the new angular speed ?